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Math4202Topology II (Lecture 26)

Math4202 Topology II (Lecture 26)

Algebraic Topology

Deformation Retracts and Homotopy Type

Lemma of homotopy equivalence

Let f,g:XYf,g:X\to Y be continuous maps. let

f=π1(X,f(x0))andg=π1(Y,g(x0))f_*=\pi_1(X,f(x_0))\quad\text{and}\quad g_*=\pi_1(Y,g(x_0))

And H:X×IYH:X\times I\to Y is a homotopy from ff to gg with a path H(x0,t)=α(t)H(x_0,t)=\alpha(t) for all tIt\in I.

Then α^f=[αˉ(fγ)α]=[gγ]=g\hat{\alpha}\circ f_*=[\bar{\alpha}*(f\circ \gamma)*\alpha]=[g\circ \gamma]=g_*. where γ\gamma is a loop in XX based at x0x_0.

Proof

$I\times I\xrightarrow{\gamma_{id}} X\times I\xrightarrow{H} Y$
  • I×{0}fγI\times \{0\}\mapsto f\circ\gamma
  • I×{1}gγI\times \{1\}\mapsto g\circ\gamma
  • {0}×Iα\{0\}\times I\mapsto \alpha
  • {1}×Iα\{1\}\times I\mapsto \alpha

As I×II\times I is convex, I×{0}({0}×I)(I×{1})({1}×I)I\times \{0\}\simeq (\{0\}\times I)*(I\times \{1\})*(\{1\}\times I).

Corollary for homotopic continuous maps

Let h,kh,k be homotopic continuous maps. And let h(x0)=y0,k(x0)=y1h(x_0)=y_0,k(x_0)=y_1. If h:π1(X,x0)π1(Y,y0)h_*:\pi_1(X,x_0)\to \pi_1(Y,y_0) is injective, then k:π1(X,x0)π1(Y,y1)k_*:\pi_1(X,x_0)\to \pi_1(Y,y_1) is injective.

Proof

α^\hat{\alpha} is an isomorphism of π1(Y,y0)\pi_1(Y,y_0) to π1(Y,y1)\pi_1(Y,y_1).

Corollary for nulhomotopic maps

Let h:XYh:X\to Y be nulhomotopic. Then h:π1(X,x0)π1(Y,h(x0))h_*:\pi_1(X,x_0)\to \pi_1(Y,h(x_0)) is a trivial group homomorphism (mapping to the constant map on h(x0)h(x_0)).

Theorem for fundamental group isomorphism by homotopy equivalence

Let f:XYf:X\to Y be a continuous map. Let f(x0)=y0f(x_0)=y_0. If ff is a homotopy equivalence  (g:YX\exists g:Y\to X such that fgidXfg\simeq id_X, gfidYgf\simeq id_Y), then

f:π1(X,x0)π1(Y,y0)f_*:\pi_1(X,x_0)\to \pi_1(Y,y_0)

is an isomorphism.

Proof

Let g:YXg:Y\to X be the homotopy inverse of ff.

Then,

fg=αidπ1(Y,y0)=αf_*\circ g_*=\alpha \circ id_{\pi_1(Y,y_0)}=\alpha

And gf=αˉidπ1(X,x0)=αˉg_*\circ f_*=\bar{\alpha}\circ id_{\pi_1(X,x_0)}=\bar{\alpha}

So f(gα^1)=idπ1(X,x0)f_*\circ (g_*\circ \hat{\alpha}^-1)=id_{\pi_1(X,x_0)}

And g(fα^1)=idπ1(Y,y0)g_*\circ (f_*\circ \hat{\alpha}^-1)=id_{\pi_1(Y,y_0)}

So ff_* is an isomorphism (have left and right inverse).

Fundamental group of higher dimensional sphere

π1(Sn,x0)={e}\pi_1(S^n,x_0)=\{e\} for n2n\geq 2.

We can decompose the sphere to the union of two hemisphere and compute π1(S+n,x0)=π1(Sn,x0)={e}\pi_1(S^n_+,x_0)=\pi_1(S^n_-,x_0)=\{e\}

But for n2n\geq 2, S+nSn=Sn1S^n_+\cap S^n_-=S^{n-1}, where S+1S1S^1_+\cap S^1_- is two disjoint points.

Theorem for “gluing” fundamental group

Suppose X=UVX=U\cup V, where UU and VV are open subsets of XX. Suppose that UVU\cap V is path connected, and xUVx\in U\cap V. Let i,ji,j be the inclusion maps of UU and VV into XX, the images of the induced homomorphisms

i:π1(U,x0)π1(X,x0)j:π1(V,x0)π1(X,x0)i_*:\pi_1(U,x_0)\to \pi_1(X,x_0)\quad j_*:\pi_1(V,x_0)\to \pi_1(X,x_0)

The image of the two map generate π1(X,x0)\pi_1(X,x_0).

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