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Math4202Exam reviewsMath4202 Topology II Exam 1 Practice

Math4202 Topology II Exam 1 Practice

In the following, please provide complete proof of the statements and the answers you give. The total score is 25 points.

Problem 1

  • (2 points) State the definition of a topological manifold.

A topological manifold is a topological space that satisfies the following:

  1. It is Hausdorff
  2. It has a countable basis
  3. Each point of xx of XX has a neighborhood that is homeomorphic to an open subset of Rm\mathbb{R}^m.
  • (2 points) Prove that real projective space RP2\mathbb{R}P^2 is a manifold.

Let RP2=R3/\mathbb{R}P^2=\mathbb{R}^3/\sim where (x,y,z)(x,y,z)(x,y,z)\sim(x',y',z') if λ(x,y,z)=(x,y,z)\lambda(x,y,z)=(x',y',z') for some λR,λ0\lambda\in \mathbb{R},\lambda\neq 0.

  1. It is Hausdorff since R3\mathbb{R}^3 is Hausdorff, subspace of Hausdorff space is Hausdorff.
  2. It has a countable basis since R3\mathbb{R}^3 has a countable basis, subspace of countable basis has countable basis.
  3. Each point of xx of RP2RP^2 has a neighborhood that is homeomorphic to an open subset of R3\mathbb{R}^3. Let pp be an arbitrary point in RP2RP^2, Consider the projection on to the tangent plane of pp defined as RP2R2\mathbb{R}P^2\to \mathbb{R}^2.

Solution on class

Consider RPn\mathbb{R} P^n be the lines in Rn+1\mathbb{R}^{n+1} through the origin.

RPn={v0vRn+1}/\mathbb{R}P^n=\{v\neq 0|v\in \mathbb{R}^{n+1}\}/\sim

where aba\sim b if there exists λR,λ0\lambda\in \mathbb{R},\lambda\neq 0 such that λa=b\lambda a=b.

Sn={vRn+1v=1}S^n=\{v\in \mathbb{R}^{n+1}|||v||=1\}

First we test the local euclidean structure.

Consider the hemisphere cap U1,+={(x1,,xn+1)x1>0}U_{1,+}=\{(x_1,\dots,x_{n+1})|x_1>0\}, note that this cap induce a quotient mapping to some open set of RPn\mathbb{R}P^n

Note that the cap U1,+U_{1,+} is local euclidean by the bijective projection map to Rn\mathbb{R}^n (x1,,xn+1)(x2,,xn+1)(x_1,\dots,x_{n+1})\mapsto(x_2,\dots,x_{n+1}).

And with U1,,U2,+,U2,,,Un,+,Un,U_{1,-},U_{2,+},U_{2,-},\dots,U_{n,+},U_{n,-} we can construct a open cover of RPn\mathbb{R}P^n. Since for any of the point in RPn\mathbb{R} P^n we can have some non-zero coordinates that projects to SnS^n and we can build such cap.

Second we show the second countability.

Take the cap with rational coordinates, and this creates a countable basis.

Third we prove the Hausdorff property.

Consider x=(x1,,xn+1)RPnx=(x_1,\dots,x_{n+1})\in \mathbb{R}P^n, y=(y1,,yn+1)RPny=(y_1,\dots,y_{n+1})\in \mathbb{R}P^n.

  • (2 points) Find a 2-1 covering space of RP2RP^2.

Take RP2S2\mathbb{R}P^2\to S^2 with quotient topology where vvv\sim -v.

Problem 2

  • (2 points) State the definition of a CW complex.

Let X0X_0 be arbitrary set of points, and XnX_n be a CW complex defined by Xn={(eαn,φα)φα:eαnXn1}=(αAeαn)Xn1X_n=\{(e_\alpha^n,\varphi_\alpha)|\varphi_\alpha: \partial e_\alpha^n\to X_{n-1}\}=(\sqcup_{\alpha\in A}e_\alpha^n)\sqcup X_{n-1}

  • (4 points) Describe a CW complex homeomorphic to the 2-torus.

Take two points a,ba,b, connect a,ba,b with two lines, and add aa with a circle connecting to itself, bb with a circle connecting to itself. Then wrap a 2-cell on that.

Problem 3

  • (2 points) State the definition of the fundamental group of a topological space XX relative to x0Xx_0 \in X.

The fundamental group of XX relative to x0x_0 is the group of all continuous paths from x0x_0 to x0x_0 under path homotopy equivalence.

  • (4 points) Compute the fundamental group of RnR^n relative to the origin.

The fundamental group of RnR^n relative to the origin is the trivial group.

Problem 4

  • (2 points) Give a pair of spaces that are homotopic equivalent, but not homeomorphic.

R\mathbb{R} and one point set is homotopic equivalent, (using contraction), but not homeomorphic.

  • (4 points) Let AA be a subspace of RnR^n, and h:(A,a0)(Y,y0)h : (A, a_0) \to (Y, y_0). Show that if hh is extendable to a continuous map of RnR^n into YY, then h:π1(A,a0)π1(Y,y0)h_* : \pi_1(A, a_0) \to \pi_1(Y, y_0) is the trivial homomorphism (the homomorphism that maps everything to the identity element).

Since hh is extendable to a continuous map of Rn\R^n into YY, consider the continuous function H:(Rn,x0)(Y,y0)H:(\R^n, x_0)\to (Y,y_0), with HA(f)=h(f)H|_{A}(f)=h(f).

Note that the inclusion map i:(A,x0)(Rn,x0)i:(A,x_0)\to (\R^n,x_0) induces ii_* gives a homomorphism, therefore Hi=hH\circ i=h is a homomorphism. Then h=Hih_*=H_*\circ i_*. where π1(Rn,x0)\pi_1(\R^n,x_0) is trivial since Rn\R^n is contractible.

Thus HH_* is the trivial homomorphism. Therefore hh_* is the trivial homomorphism.

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