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Math 416 Final Review

Story after Cauchy’s theorem

Chapter 7: Cauchy’s Theorem

Existence of harmonic conjugate

Suppose f=u+ivf=u+iv is holomorphic on a domain UCU\subset\mathbb{C}. Then u=fu=\Re f is harmonic on UU. That is Δu=2ux2+2uy2=0\Delta u=\frac{\partial^2 u}{\partial x^2}+\frac{\partial^2 u}{\partial y^2}=0.

Moreover, there exists gO(U)g\in O(U) such that gg is unique up to an additive imaginary constant.

Example:

Find a harmonic conjugate of u(x,y)=logzz1u(x,y)=\log|\frac{z}{z-1}|

Note that log(zz1)=logzz1+i(arg(z)arg(z1))\log(\frac{z}{z-1})=\log \left|\frac{z}{z-1}\right|+i(\arg(z)-\arg(z-1)) is harmonic on C{1}\mathbb{C}\setminus\{1\}.

So the harmonic conjugate of u(x,y)=logzz1u(x,y)=\log|\frac{z}{z-1}| is v(x,y)=arg(z)arg(z1)+Cv(x,y)=\arg(z)-\arg(z-1)+C where CC is a constant.

Note that the harmonic conjugate may exist locally but not globally. (e.g. u(x,y)=logz(z1)u(x,y)=\log|z(z-1)| has a local harmonic conjugate i(arg(z)+arg(z1)+C)i(\arg(z)+\arg(z-1)+C) but this is not a well defined function since arg(z)+arg(z1)\arg(z)+\arg(z-1) is not single-valued.)

Corollary for harmonic functions

Theorem 7.19

Harmonic function are infinitely differentiable.

Theorem 7.20

Mean value property of harmonic functions.

Let uu be harmonic on an open set of Ω\Omega, then

u(z0)=12π02πu(z0+reiθ)dθu(z_0)=\frac{1}{2\pi}\int_0^{2\pi} u(z_0+re^{i\theta}) d\theta

for any z0Ωz_0\in\Omega and r>0r>0 such that D(z0,r)ΩD(z_0,r)\subset\Omega.

Theorem 7.21

Identity theorem for harmonic functions.

Let uu be harmonic on a domain Ω\Omega. If u=0u=0 on some open set GΩG\subset\Omega, then u0u\equiv 0 on Ω\Omega.

Theorem 7.22

Maximum principle for harmonic functions.

Let uu be a non-constant real-valued harmonic function on a domain Ω\Omega. Then u|u| does not attain a maximum value in Ω\Omega.

Chapter 8: Laurent Series and Isolated Singularities

Laurent Series

Laurent series is a generalization of Taylor series.

Laurent series is a power series of the form

f(z)=n=an(zz0)nf(z)=\sum_{n=-\infty}^{\infty} a_n (z-z_0)^n

where

ak=12πiCrf(z)(zz0)k+1dza_k=\frac{1}{2\pi i}\int_{C_r}\frac{f(z)}{(z-z_0)^{k+1}}dz

The series converges on an annulus R1<zz0<R2R_1<|z-z_0|<R_2.

where R1=lim supnan1/nR_1=\limsup_{n\to\infty} |a_{-n}|^{1/n} and R2=1lim supnan1/nR_2=\frac{1}{\limsup_{n\to\infty} |a_n|^{1/n}}.

Cauchy’s Formula for an Annulus

Let ff be holomorphic on an annulus R1<r1<zz0<r2<R2R_1<r_1<|z-z_0|<r_2<R_2. And wA(z0;R1,R2)w\in A(z_0;R_1,R_2). Find the Annulus wA(z0;r1,r2)w\in A(z_0;r_1,r_2)

Then

f(w)=12πiCr1f(z)zwdz12πiCr2f(z)zwdzf(w)=\frac{1}{2\pi i}\int_{C_{r_1}}\frac{f(z)}{z-w}dz-\frac{1}{2\pi i}\int_{C_{r_2}}\frac{f(z)}{z-w}dz

Isolated singularities

Let ff be holomorphic on 0<zz0<R0<|z-z_0|<R (The punctured disk of radius RR centered at z0z_0). If there exists a Laurent series of ff convergent on 0<zz0<R0<|z-z_0|<R, then z0z_0 is called an isolated singularity of ff.

The series f(z)=n=1an(zz0)nf(z)=\sum_{n=-\infty}^{-1}a_n(z-z_0)^n is called the principle part of Laurent series of ff at z0z_0.

Removable singularities

If the principle part of Laurent series of ff at z0z_0 is zero, then z0z_0 is called a removable singularity of ff.

Criterion for a removable singularity:

If ff is bounded on 0<zz0<R0<|z-z_0|<R, then z0z_0 is a removable singularity.

Example:

f(z)=1ez1f(z)=\frac{1}{e^z-1} has a removable singularity at z=0z=0.

The Laurent series of ff at z=0z=0 is

f(z)=1z+n=0znn!f(z)=\frac{1}{z}+\sum_{n=0}^{\infty}\frac{z^n}{n!}

The principle part is zero, so z=0z=0 is a removable singularity.

Poles

If the principle part of Laurent series of ff at z0z_0 is a finite sum, then z0z_0 is called a pole of ff.

Criterion for a pole:

If ff has an isolated singularity at z0z_0, and limzz0f(z)=\lim_{z\to z_0}|f(z)|=\infty, then z0z_0 is a pole of ff.

Example:

f(z)=1z2f(z)=\frac{1}{z^2} has a pole at z=0z=0.

The Laurent series of ff at z=0z=0 is

f(z)=1z2f(z)=\frac{1}{z^2}

The principle part is 1z2\frac{1}{z^2}, so z=0z=0 is a pole.

Essential singularities

If ff has an isolated singularity at z0z_0, and it is neither a removable singularity nor a pole, then z0z_0 is called an essential singularity of ff.

“Criterion” for an essential singularity:

If the principle part of Laurent series of ff at z0z_0 has infinitely many non-zero coefficients corresponding to negative powers of zz0z-z_0, then z0z_0 is called an essential singularity of ff.

Example:

f(z)=sin(1z)f(z)=\sin(\frac{1}{z}) has an essential singularity at z=0z=0.

The Laurent series of ff at z=0z=0 is

f(z)=1z16z3+1120z5f(z)=\frac{1}{z}-\frac{1}{6z^3}+\frac{1}{120z^5}-\cdots

Since there are infinitely many non-zero coefficients corresponding to negative powers of zz, z=0z=0 is an essential singularity.

Singularities at infinity

We say ff has a singularity (removable, pole, or essential) at infinity if f(1/z)f(1/z) has an isolated singularity (removable, pole, or essential) at z=0z=0.

Example:

f(z)=z4(z1)(z3)f(z)=\frac{z^4}{(z-1)(z-3)} has a pole of order 2 at infinity.

Plug in z=1/wz=1/w, we get f(1/w)=1w21(1/w1)(1/w3)=1w21(1w)(13w)=1w2(1+O(w))f(1/w)=\frac{1}{w^2}\frac{1}{(1/w-1)(1/w-3)}=\frac{1}{w^2}\frac{1}{(1-w)(1-3w)}=\frac{1}{w^2}(1+O(w)), which has pole of order 2 at w=0w=0.

Residue

The residue of ff at z0z_0 is the coefficient of the term (zz0)1(z-z_0)^{-1} in the Laurent series of ff at z0z_0.

Example:

f(z)=1z2f(z)=\frac{1}{z^2} has a residue of 0 at z=0z=0.

f(z)=z3z1f(z)=\frac{z^3}{z-1} has a residue of 1 at z=1z=1.

Residue for pole with higher order:

If ff has a pole of order nn at z0z_0, then the residue of ff at z0z_0 is

res(f,z0)=1(n1)!limzz0dn1dzn1((zz0)nf(z))\operatorname{res}(f,z_0)=\frac{1}{(n-1)!}\lim_{z\to z_0}\frac{d^{n-1}}{dz^{n-1}}((z-z_0)^nf(z))

Chapter 9: Generalized Cauchy’s Theorem

Winding number

The winding number of a closed curve CC with respect to a point z0z_0 is

indC(z0)=12πiC1zz0dz\operatorname{ind}_C(z_0)=\frac{1}{2\pi i}\int_C\frac{1}{z-z_0}dz

the winding number is the number of times the curve CC winds around the point z0z_0 counterclockwise. (May be negative)

Contour integrals

A contour is a piecewise continuous curve γ:[a,b]C\gamma:[a,b]\to\mathbb{C} with integer coefficients.

Γ=i=1pnjγj\Gamma=\sum_{i=1}^p n_j\gamma_j

where γj:[aj,bj]C\gamma_j:[a_j,b_j]\to\mathbb{C} is continuous closed curve and njZn_j\in\mathbb{Z}.

Interior of a curve

The interior of a curve is the set of points zCz\in\mathbb{C} such that indΓ(z)0\operatorname{ind}_{\Gamma}(z)\neq 0.

The winding number of contour Γ\Gamma is the sum of the winding numbers of the components of Γ\Gamma around z0z_0.

indΓ(z)=j=1pnjindγj(z)\operatorname{ind}_{\Gamma}(z)=\sum_{j=1}^p n_j\operatorname{ind}_{\gamma_j}(z)

Separation lemma

Let ΩC\Omega\subseteq\mathbb{C} be a domain and KΩK\subset \Omega be compact. Then there exists a simple contour ΓΩK\Gamma\subset \Omega\setminus K such that KintΓ(Γ)ΩK\subset \operatorname{int}_{\Gamma}(\Gamma)\subset \Omega.

Key idea:

Let 0<δ<d(K,Ω)0<\delta<d(K,\partial \Omega), then draw the grid lines and trace the contour.

Residue theorem

Let Ω\Omega be a domain, Γ\Gamma be a contour such that Γint(Γ)Ω\Gamma\cap \operatorname{int}(\Gamma)\subset \Omega. Let ff be holomorphic on Ω{z1,z2,,zp}\Omega\setminus \{z_1,z_2,\cdots,z_p\} and z1,z2,,zpz_1,z_2,\cdots,z_p are finitely many points in Ω\Omega, where z1,z2,,zpΓz_1,z_2,\cdots,z_p\notin \Gamma. Then

Γf(z)dz=2πij=1pres(f,zj)\int_{\Gamma}f(z)dz=2\pi i\sum_{j=1}^p \operatorname{res}(f,z_j)

Key: Prove by circle around each singularity and connect them using two way paths.

Homotopy*

Suppose γ0,γ1\gamma_0, \gamma_1 are two curves from [0,1][0,1] to Ω\Omega with same end points P,QP,Q.

A homotopy is a continuous function of curves γt,0t1\gamma_t, 0\leq t\leq 1, deforming γ0\gamma_0 to γ1\gamma_1, keeping the end points fixed.

Formally, if H:[0,1]×[0,1]ΩH:[0,1]\times [0,1]\to \Omega is a continuous function satsifying

  1. H(s,0)=γ0(s)H(s,0)=\gamma_0(s), s[0,1]\forall s\in [0,1]
  2. H(s,1)=γ1(s)H(s,1)=\gamma_1(s), s[0,1]\forall s\in [0,1]
  3. H(0,t)=PH(0,t)=P, t[0,1]\forall t\in [0,1]
  4. H(1,t)=QH(1,t)=Q, t[0,1]\forall t\in [0,1]

Then we say HH is a homotopy between γ0\gamma_0 and γ1\gamma_1. (If γ0\gamma_0 and γ1\gamma_1 are closed curves, Q=PQ=P)

Lemma 9.12 Technical Lemma

Let ϕ:[0,1]×[0,1]C{0}\phi:[0,1]\times [0,1]\to \mathbb{C}\setminus \{0\} is continuous. Then there exists a continuous map ψ:[0,1]×[0,1]C\psi:[0,1]\times [0,1]\to \mathbb{C} such that eϕ=ψe^\phi=\psi. Moreover, ψ\psi is unique up to an additive constant in 2πiZ2\pi i\mathbb{Z}.

General approach to evaluate definite integrals

Choose a contour so that one side is the desired integral.

Handle the other sides using:

  • Symmetry
  • Favorite estimate
  • Bound function by another function whose integral goes to 0
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